Calculate the mass of photon with wavelength 3.6 angstrom

Lets understand how to calculate the mass of photon with wavelength 3.6 angstrom

How much energy does a photon contain?

A photon is a subatomic particle with no mass or charge. If we assume that a photon has zero rest mass (which is true), then its total energy would be equal to its momentum multiplied by c squared.

We can calculate the mass of a photon using the equation E mc2. In this case, the energy of the photon is equal to its momentum times the speed of light squared.

For our question we will use de-brogile’s equation

Solution:

  • Let lamda = 3.6 angstrom = 3.6 x 10^-10 m.
  • Implied velocity of photon = velocity of light.
  • m = h/lamda*v ( Using de-brogile’s equation)
  • m = 6.626 x 10^-34/3.6 x10^-10 x 3 x 10^8
  • m = 6.626 x 10^-32/10.8
  • m = 0.6135 x 10^-32
  • m = 6.135 x 10^-33 kg.

6.135 x 10^-33 kg

is the answer

So in short for the question

How to calculate the mass of photon with wavelength 3.6 angstrom?

Using Formulas
λ = h / MV and M = h / λV
—————————–
Where
M = mass of proton
h = planck’s constant
λ =  Wave length
V = Velocity
——————————–
λ = 3.6 A⁰ = 3.6 × 10⁻¹⁰ m
h = 6.626 × 10 ⁻³⁴ 
V  =  3 × 10⁸ m/s 
———————————
∴ M = ( 6.626 × 10 ⁻³⁴ ) / [ ( 3.6 × 10⁻¹⁰ ) × ( 3 × 10⁸)]
       = 6. 135 × 10⁻³³ kg 

How much does a single photon weigh?

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