Lets understand how to calculate the mass of photon with wavelength 3.6 angstrom

We will use de-brogile’s equation

**Solution:**

- Let lamda = 3.6 angstrom = 3.6 x 10^-10 m.
- Implied velocity of photon = velocity of light.
- m = h/lamda*v ( Using de-brogile’s equation)
- m = 6.626 x 10^-34/3.6 x10^-10 x 3 x 10^8
- m = 6.626 x 10^-32/10.8
- m = 0.6135 x 10^-32
- m = 6.135 x 10^-33 kg.

So in short for the question

### How to calculate the mass of photon with wavelength 3.6 angstrom?

Using Formulas

λ = h / MV and M = h / λV

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Where

M = mass of proton

h = planck’s constant

λ = Wave length

V = Velocity

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λ = 3.6 A⁰ = 3.6 × 10⁻¹⁰ m

h = 6.626 × 10 ⁻³⁴

V = 3 × 10⁸ m/s

———————————

∴ M = ( 6.626 × 10 ⁻³⁴ ) / [ ( 3.6 × 10⁻¹⁰ ) × ( 3 × 10⁸)]

= 6. 135 × 10⁻³³ kg