This question comes under prime factorization topic and in this case, we need to find a number which when multiplied to the given number results in having 3 prime factors. Note that 43 itself is a prime number so we need to find the other 2 prime numbers (factors).

Quick Answer is 6. Keep Reading below for Explanation |

## But first, what is a Prime Number?

A prime number is a number that is only divisible by itself and 1. so here you can say 1 and the number itself are factors.

## Prime number list:

Prime number list is **2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89** and so on

So now to find the number to be multiplied to 43 we start by multiplying prime numbers from the** prime number list** ( 2 ,3 ,5 ,7 ….).

2 x 43 ( 2 is a prime number )

3 x 43 ( 3 is also a prime number)

So we get 2 prime factors ( 2 and 3) and the 3rd one is 43.

multiplying all we get 2 x 3 x 43 = 258

### Coming back to our question , Which number should be multiplied by 43 so that it will have 3 prime factors?

Since 43 is already there we have 2 and 3

and since we have to make it to a single-digit number so it becomes

2 x 3 = 6

So 6 is the number to be multiplied to 43 to get 3 prime factors ( 2 , 3 and 43 )

## FAQ

### What is Prime Factorization?

*Prime factorization* is a method to find the **prime **factors of a given number. These factors are nothing but prime numbers.

### What is the difference between Prime number and Prime Factor?

Prime Factors are the prime number which when multiplied give the resultant composite number.

### Is 1 a prime number?

No, as it is understood that a prime number should be divisible by 2 numbers 1 and itself. In case of 1 we have one only factor equal to 1.

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