This question comes under prime factorization topic and in this case, we need to find a number which when multiplied to the given number results in having 3 prime factors. Note that 43 itself is a prime number so we need to find the other 2 prime numbers (factors).
|Quick Answer is 6. Keep Reading below for Explanation|
But first, what is a Prime Number?
A prime number is a number that is only divisible by itself and 1. so here you can say 1 and the number itself are factors.
Prime number list:
Prime number list is 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89 and so on
So now to find the number to be multiplied to 43 we start by multiplying prime numbers from the prime number list ( 2 ,3 ,5 ,7 ….).
2 x 43 ( 2 is a prime number )
3 x 43 ( 3 is also a prime number)
So we get 2 prime factors ( 2 and 3) and the 3rd one is 43.
multiplying all we get 2 x 3 x 43 = 258
Coming back to our question , Which number should be multiplied by 43 so that it will have 3 prime factors?
Since 43 is already there we have 2 and 3
and since we have to make it to a single-digit number so it becomes
2 x 3 = 6
So 6 is the number to be multiplied to 43 to get 3 prime factors ( 2 , 3 and 43 )
What is Prime Factorization?
Prime factorization is a method to find the prime factors of a given number. These factors are nothing but prime numbers.
What is the difference between Prime number and Prime Factor?
Prime Factors are the prime number which when multiplied give the resultant composite number.
Is 1 a prime number?
No, as it is understood that a prime number should be divisible by 2 numbers 1 and itself. In case of 1 we have one only factor equal to 1.