[Explained] SF6 is known but SH6 is not known.

SF6 is known but SH6 is not known Lets analyze :

SF6 is known because Fluorine (F) is a strong oxidizing agent that means it under go reduction and oxidize Sulphur(S) to its maximum oxidation state i.e. +6.

             Whereas H2 is a weak oxidizing agent, so cannot oxidize S to its maximum oxidation state of +6, hence does not form SH6.

 F is the most electronegative element and that’s why it can use all the 6 electron of sulphur but hydrogen can’t do so as it is not much electronegative

So the answer to question

Why SF6 is known but SH6 is not known?

Since SF₆ is a strong oxidizing agent can exhibit oxidation number +6 whereas SH₆ being a weak oxidizing agent can’t expand oxidation number +6. That’s the reason its not known

Chemistry

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