CFSE for high spin d4 octahedral complex is

In this question, we have to find the Crystal field stabilisation energy: cfse for high spin d4 octahedral complex is

Options are

A –0.6Δ_oct

B–1.8Δ_oct

C–1.6Δ_oct

D–1.2Δ_oct

Solution

As we know high spin is due to a weak ligand , hence pairing up of electrons does not take place.

in case of high spin complex, Δ0​ is small. Thus, the energy required to pair up the fourth electron with the electrons of lower energy d-orbitals would be higher than that required to place the electrons in the higher d-orbital. Thus, pairing does not occur.
For high spin d4 octahedral complex Crystal field stabilisation energy

The following figure shows the filling of electrons in the subshells.

△oct=1×(3/5)−[3×(2/5)]
△oct=−0.6△oct

The correct option is A –0.6Δ_oct

The correct option is  –0.6Δ_oct

therefore the answer to the question

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